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In parallelogram ABCD, AB>BC. Point P lies on diagonal AC so that P is equidistant from both AB and BC. SImilarly point Q lies on AC so that Q is equidistant from both CD and AD. If PQ = AC/4, find the ratio of AB:BC

Plz help, I'm stuck...

2007-12-08 10:49:30 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

Triangles ABP and CBP are similar (identical angles).

AB / BC = AP / CP = (5/8 AC) / (3/8 AC) = 5/3

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2007-12-08 14:09:08 · answer #1 · answered by oregfiu 7 · 1 0

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