An sp3d hybridized atom is bonded to two other atoms, why is it linear and not bent Use VSEPR repulsion angles

Answer 1

this is like a carbon dioxide (O=C=O) and basically, the carbon has two bonds to each oxygen, and since the valence shell electrons on each oxygen have a negative charge, they repel as much as possible (being on completely opposite sides of carbon). This forms a linear arrangement (line of atoms). If it were bent the electrons would be closer together making the atom higher in energy and therefore less stable. (stability is the driving force for many reactions).

Answer 2

I don't quite understand your question. A fully-bonded sp3 hybrid atom would be at the center of a tetrahedron, with with the other bonded atoms at the four corners. If only two atoms are bonded to it, the two atoms in space define a line, which is old plane geometry. With water and ammonia, the unbonded electrons in orbitals do alter the angle between the central atom and the other two, which would be 109.5 degreesfor a perfect tetrahedron. Since they represent highly electronegative areas, they force the other two bonds to a more acute angle. I believe that in water, the angle is 92 degrees.