Can someone tell me how to figure this math question out????

Question

If Sally can paint the house in 4 hours and John can paint the same house in 6 hours how long will it take the both of them to paint the house together??

Answer 1

Let S be the rate at which Sally works and J be John's rate.

S = 1 / 4 and J = 1 / 6

T ( 1 / 4 ) + T ( 1 / 6 ) = 1

3 T / 12 + 2 T / 12 = 1

5 T / 12 = 1

T = 12 / 5

Working together, they can paint the house in 2 2/5 hours.

Added later: other submitters seem to think that the answer is five hours. Sorry, folks - if Sally can do it by herself in four, it ain't gonna take longer when John pitches in unless he's a total klutz or they spend all their time flirting.

Answer 2

Sally paints 1/4 of the house in an hour
John paints 1/6 of the house in an hour
Together they paint 5/12 of the house in an hour

1 / (5/12) = 2 2/5 hours

Answer 3

in one hour, Sallly paints 1/4 house and John paints 1/6 house. Together, they paint 1/4 + 1/6 = 5/12 house
(if they don't waste time flirting).

So they will finish in 12/5 hours = 2 hrs 24 minutes

Answer 4

Sally rate = 1 house in 4 hours

John rate = 1 house in 6 hours

Add the rates

1/4 + 1/6 = 1/h

3h + 2h = 12 {*12h, the LCD}

5h = 12

h = 2.4 hours

Answer 5

5 hours. Add the hours together and divide by the number of painters to get the time it will take. Simple Problem Solving

Answer 6

i would think it would be less then 4 hours but im not sure, i would guess 2 tho

Answer 7

918 HOURS FO

Answer 8

i dont get it