Correct me if i'm wrong:
the Quadratic formula is :
x = -b ± √(b^2 - 4ac) / 2a
?
is that correct?
2007-12-08 08:21:31 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Almost...make sure you understand that the -b is part of the numerator as well...
x = [ -b ± √(b^2 - 4ac) ] / 2a
2007-12-08 08:25:08 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
x = [-b ± â(b^2 - 4ac)]/ 2a
You needed an extra bracket pair
2007-12-08 08:25:22 · answer #2 · answered by kindricko 7 · 0⤊ 0⤋
x = [-b ± â(b^2 - 4ac)] / 2a
2007-12-08 08:24:18 · answer #3 · answered by ben e 7 · 1⤊ 0⤋
The '-b' is also divided by 2a
2007-12-08 08:27:13 · answer #4 · answered by haydenriach 2 · 0⤊ 0⤋
yes.
2007-12-08 08:23:07 · answer #5 · answered by Alex S 2 · 1⤊ 1⤋
Yes that is it! :)
2007-12-08 08:24:14 · answer #6 · answered by cheeseywonder 1 · 0⤊ 1⤋