difference of the squares of the other two sides?
true or false
2007-12-08 07:51:49 · 12 answers · asked by Donny 2 in Science & Mathematics ➔ Mathematics
Sum of the squares on the other two sides.
False
2007-12-08 07:53:54 · answer #1 · answered by A A 3 · 1⤊ 0⤋
No the addition of the two other sides. Triangle of hypotenuse c and sides a and b, would be a^2+b^2=c^2.
2007-12-08 07:55:21 · answer #2 · answered by R.S.A.B.C.R.D.A 2 · 0⤊ 0⤋
Hey there!
False. For any right triangle, whose legs are a and b, and the hypotenuse is c, then by the Pythagorean Theorem:
a^2+b^2=c^2
Not
a^2-b^2=c^2
So the answer is false.
Hope it helps!
2007-12-08 07:54:54 · answer #3 · answered by ? 6 · 1⤊ 0⤋
the sum of the square of the two legs of a right triangle is equal to the square of the hypotenuse of the right triangle.
2007-12-08 07:58:02 · answer #4 · answered by Michael K 1 · 0⤊ 0⤋
A^2+B^2=c^2 works as a better model when you use the 3-4-5 rule to compare to your thought. 3^2+4^2=25 which would be c^2; if you took 3+4=7 then go 7^2 you would get a wrong answer even after you get the square root.
2016-04-08 01:58:43 · answer #5 · answered by ? 4 · 0⤊ 0⤋
The pythagorean theorem is pretty a2+b2=c2
A2 is the bottom, b2 is the side, and c2 is the hypotenous. so if the triangle is 2 by 3 then the hypotenous is the square root of 13.
2007-12-08 07:57:32 · answer #6 · answered by Rian M 2 · 0⤊ 0⤋
False.
Its equal to the sum of the squares of the other two sides.
2007-12-08 07:55:04 · answer #7 · answered by Elana 7 · 0⤊ 0⤋
a^2 + b^2 = c^2
Both sides are squared, and the sum is hte square of the hypotenuse, or side c.
False
2007-12-08 07:59:27 · answer #8 · answered by Camoen 2 · 0⤊ 0⤋
false. It is the sum of the squares of the other sides
2007-12-08 07:54:46 · answer #9 · answered by ironduke8159 7 · 0⤊ 0⤋
not the difference the sum.
a squared = b squared = c squared
where 'a' and 'b' are base and height, and c is the hypotenuse
2007-12-08 07:55:42 · answer #10 · answered by popofosho 3 · 0⤊ 0⤋