How do I do this?!
2007-12-08 06:55:01 · 5 answers · asked by immagirlinvegas 1 in Science & Mathematics ➔ Mathematics
2x+3y=6
Rearrange to get
3y = 6 - 2x
y = 2 - 2x / 3
Now, the y-intercept is the value of y when x = 0, so set x = 0
y = 2 - 0 = 2
So the y-intercept is at x = 0, y = 2.
2007-12-08 06:59:28 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
Hello there,
Any y-intercept (aka ordinate) is on the x-axis; that is, any ordinate is on x = 0. Do you understand why?
There are two methods to solving this problem:
1. We can substitute x = 0 into your equation:
2(0) + 3y = 6
3y = 6
y = 2 <-- There's your ordinate.
2. Rewrite equation in the form y = mx + b (b is the ordinate):
2x + 3y = 6
3y = -2x + 6
y = (-2/3)x + 2
y = 2 <-- There it is again.
As you can see, both methods work. Hope this helps!
2007-12-08 15:00:38 · answer #2 · answered by scherz0 3 · 1⤊ 0⤋
2x+3y=6
3y = -2x + 6
y=-2/3x + 2
y= mx + c
where c is the y-intercept which is 2
2007-12-08 14:58:34 · answer #3 · answered by Murtaza 6 · 0⤊ 0⤋
arrange the given equation in form of y=mx+c
2x+3y=6
3y = -2x+6
y = (-2/3)x + 2
put x=0 and solve for y
y = +2
2007-12-08 15:01:27 · answer #4 · answered by (ƸӜƷ) 1 · 0⤊ 0⤋
x=0
3y=6
y=2
2007-12-08 14:58:41 · answer #5 · answered by Anonymous · 0⤊ 0⤋