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Question

What is the molarity of K+ ions that a solution of 3.49M of K2SO3 will have?


many thanks!!!

Answer 1

Every mole of K2SO3 will dissociate into two moles of K+ ions. Thus, a 3.49M solution of K2SO3 will have a K+ concentration of 3.49Mx2, or 6.98M.

Answer 2

When potassium sulphite is dissolved in water the formula is:-

K2SO3(aq) = 2K+(aq) + SO3-(aq)

By the molar ratios :-

K2SO3 : K+ : SO3- :: 1:2:1

So 1 mole of K2SO3 will produce 2 moles K+
Therefore:-
2.49 moles K2SO3 will produce 2.49 x 2 moles K+
2.49 x 2 = 4.98 moles (K+) the Answer.