Math Problem?

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The width of a rectangle is 5 feet less than its length. If the perimeter of the rectangle is 66 feet, find the dimensions of the rectangle.

2007-12-08 05:02:21 · 2 answers · asked by bobby m 1 in Science & Mathematics ➔ Mathematics

2 answers

Let l be the length. Let w be the width.
w = l-5
2w + 2l = 66
2(l-5) + 2l = 66
2l - 10 + 2l = 66
4l = 76
l = 19
w = 19-5 = 14
so 14x19 are the dimensions.

2007-12-08 05:07:01 · answer #1 · answered by highschoolmathpreparation 3 · 0⤊ 0⤋

let l be the length, l-5 is the width

2(l + l- 5) = 66
4l - 10 = 66
4l = 76
l = 19
w = 14

dimensions of rect = 19x14

2007-12-08 13:07:29 · answer #2 · answered by norman 7 · 0⤊ 0⤋