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(-4x^4 y^2 / x^3 y^5)^-3

2007-12-08 04:58:43 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

-64(x/y^3)^-3
=-64y^9/x^3

2007-12-08 05:04:35 · answer #1 · answered by norman 7 · 0 1

(-4x^4 y^2 / x^3 y^5)^-3
=(-4)^(-3) * x^(-3) *y^(9)
=(-1/64) * x^(-3) *y^(9)

2007-12-08 05:07:30 · answer #2 · answered by shanu_gupta2003 2 · 0 0

(-4x^4 y^2 / x^3 y^5)^-3
= [(-4)^-3] [(x)^-3][(y^-3)^-3]
= -y^9/(64x^3)

2007-12-08 05:06:48 · answer #3 · answered by sahsjing 7 · 0 0

You both are very smart!

2007-12-08 05:07:25 · answer #4 · answered by Anonymous · 0 0

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