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a gardener mows a lawn with an old-fashioned push mower. The handle of the mower makes an angle of 32 degree with the surface of the lawn.
a) If a 209-N force is applied along the handle of the 18-kg mower, what is the normal force exerted by the lawn on the mower?
b) If the angle between the surface of the lawn and the handle of the mower is increased, does the normal force exerted by the lawn increase, decrease, or stay the same?

2007-12-08 04:30:27 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Look at the forces on the lawn mower...

mg, down
N, straight up
H, angle 32 degrees

There's no friction mentioned so all we care about is the vertical dimension. There's no net acceleration in the vertical dimension, so the net force must be zero.

0 = N - mg - ( 209 N ) sin 32

so

N = mg + ( 209 N ) sin 32

2007-12-08 04:55:08 · answer #1 · answered by jgoulden 7 · 1 0

Resolve the 209 N force into a horizontal component and a vertical component.

The vertical component plus the weight of the mower together make up the force exerted by the mower normal to the ground.

Now look at your equation and you can answer part b.

2007-12-08 12:52:02 · answer #2 · answered by Chuck 6 · 1 0

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