find the vertex and equation of the line symmetry?

Question

1.f(x)= (x-4)^2
2.f(x)= 8x^2

Answer 1

Hi,
First I'll give you the answer; then some additional optional infromation.
1.f(x)= (x-4)^2
Vertex: (4,0)
Eqution of line of symmetry:
x=4

2.f(x)= 8x^2
Vertex: (0,0)
Line of symmetry:
X=0

The format that your problems are apparently using is this:
f(x) = a(x-h)² +k
Where "h" is the x-coordinate and "k" is the y coordinate of the vertex.

FE

Answer 2

Line Of Symmetry Equation

Answer 3

For 1. The vertex is (4,0) thus the line of symmetry is x=4.
For 2. The vertex is (0,0) thus the line of symmetry is x=0.

Just remember the general form: y = a(x-h)^2 + k and note the vertex is at the point (h,k) and since these are parabolas the line of symmetry is just x = x-coord of vertex.

Answer 4

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RE:
find the vertex and equation of the line symmetry?
1.f(x)= (x-4)^2
2.f(x)= 8x^2

Answer 5

1.f(x)= (x-4)^2
vertex: (4, 0)
line of symmetry: x = 4

2.f(x)= 8x^2
vertex: (0, 0)
line of symmetry: x = 0
--------
Ideas: Compare to the vertex form f(x) = a(x-h)^2 + k, where (h, k) is the point of vertex, and x = h is the equation of the line symmetry.

Answer 6

y=a(x-r)^2+k
V(r,k)

the line symmetry is x=r

r=-b/2a
f(r)=k

V(4,0)
the line symmetry is x=4

2)
V(0,0)
the line symmetry is x=0

Answer 7

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