a + b + i(a + b) = 6 + 4i ?

Question

the first letter is not capital.. it's all small caps..

hi.. this is an (imaginary numbers) question..

i = imaginary number

find a and b ?

i know that both both sides equal each other but i don't know whats my first step.. please help thanx!!

Answers: a = 5, b = 1

yea.. (a "-" b) makes more sense..

guys thanx alot..

Answer 1

The error is the second b should be -b
First step is to note that if
a+b + i(a-b) = 6 + 4i Then
a+b = 6 AND a-b = 4
Adding the two equations yields:
2a = 10 -> a = 5
Subbing into the first equation
5 + b = 6 -> b = 1
Solving yields a=5 and b=1 as required

Answer 2

a + b + i(a + b) = 6 + 4i

Equating real part on both the sides we get -
a + b = 6 ....................... (1)

Again equating imaginary part we get -
a + b = 4

This question is absurd. But if the question is -

a + b + i(a - b) = 6 + 4i
Then -

a +b = 6..............and
a - b = 4...........

If we solve these simultaneous eqns, we get -

a = 5 and b = 1 .................... Answer

Answer 3

This doesn't work. I'll explain why so bear with me:

If this were true, the real part on each side would have to equal each other. That means:
a + b = 6

Also, the imaginary part has to equal each other. That means:
a + b = 4

That's an impossible situation, so there is no solution. Are you sure you have all the signs right? If this indeed is the problem, there is no solution.

Hope I've helped you! :)

Answer 4

equate real parts with real parts and imaginary parts with imaginary parts:

a+b = 6
a+b = 4

oops. are you sure one of them isn't a minus b? the answer you give confirms the problem should be

a+b + i(a-b) = 6+4i

so we would have
a+b = 6
a-b = 4

add these together to get
2a=10, thus a=5, substitute 5 back in one of the equations and solve for b
5+b=6, thus b=6-5=1

Answer 5

Two complex numbers are equal only if the real parts are equal AND the imaginary parts are equal
This can only be true if
a + b = 6 AND
a + b = 4
This is NOT possible because 6 does not equal 4 EVER
________________________________________
KrazyKyngeKorny(Krazy, not stupid)
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Answer 6

equate real parts a+b=6

equate imaginary parts a+b=4


then you are supposed to solve this by simultaneous equations. I think there's an error in the question.

Answer 7

Well this is impossible

To ,do this, we would need the following to be true

a+b=6, and a+b=4

If we try to solve we get

6-a=b

a+(6-a)=4

a+6-a=4

6 = 4

The above is a fallacy, so the situation you gave is impossible.

Answer 8

it somewhat is a text fabric editor or be conscious processor reading binary as unicode characters. no longer an inherent sign of something (like viruses). no longer something to be traumatic approximately, yet whilst all you're saying is "shows up on my pc" you're no longer giving us something to artwork with.

Answer 9

5+1+i(5+1)=6+4i
6+6i=6+4i

sorry...they don't equal each other

what are you solving for in the first place?

Answer 10

a + b + i(a + b) = 6 + 4i

a+b=6
a+b=4

The solution is empty set.