2007-12-07 18:08:44 · 8 answers · asked by stricking 2 in Science & Mathematics ➔ Mathematics
(X^4-1 )/ (X-1)
factor the numerator
(X^4- 1) = (x^2 +1) * (x^2 -1) = (x^2 +1) * (x + 1) * (x -1)
(x^2 +1) * (x + 1) * (x -1) / (x-1) =
(x^2 +1) * (x + 1)
multiply it out if you want to
x^3 + x^2 + x + 1
you might want to look up "cyclotonic" on the web
2007-12-07 18:11:31 · answer #1 · answered by atheistforthebirthofjesus 6 · 0⤊ 0⤋
x^3 + x^2 + x + 1
2007-12-07 18:13:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(x+1)(x^2 +1)
2007-12-07 18:15:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
( x ² - 1 ) ( x ² + 1 ) / ( x - 1 )
( x - 1 ) ( x + 1 ) ( x ² + 1 ) / ( x - 1 )
( x + 1 ) ( x ² + 1 )
2007-12-07 23:11:06 · answer #4 · answered by Como 7 · 2⤊ 0⤋
a^n - b^n = (a - b)[(a^0) b^(n - 1) + (a^1)b^(n - 2) + ... +
+ a^(n - 1) b^0]
Plug a=x, b=1, n=4
x^4 - 1 = (x - 1)(x^3 + x^2 + x + 1)
(x^4 - 1)/(x - 1) = x^3 + x^2 + x + 1
2007-12-07 18:21:26 · answer #5 · answered by Amit Y 5 · 0⤊ 0⤋
x^4-1 / x-1=
(x^2-1)(x^2+1) /x-1
(x-1)(x+1)(x^2+1) / x-1 x-1's cancel
(x+1)(x^2+1)=x^3+x^2+x+1
2007-12-07 18:24:39 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(x^4 - 1)/(x - 1)
((x^2 - 1)(x^2 + 1))/(x - 1)
((x - 1)(x + 1)(x^2 + 1))/(x - 1)
(x + 1)(x^2 + 1)
x^3 + x + x^2 + 1
ANS : x^3 + x^2 + x + 1
2007-12-07 18:17:00 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋
(x^4-1)/(x-1)
=[(x-1)(x+1)(x-1)(x+1)]/[(x-1)].
=(x+1)(x-1)(x+1).
Break it down and cancel out an (x-1)
from the numerator and the denominator.
2007-12-07 18:16:11 · answer #8 · answered by Jeremy B 2 · 0⤊ 1⤋