Consider the function f(x) = 8 e^x - 9 (1/3x^3) - 2.
Find the general antiderivative of f(x).
FOR SOME REASON...IT KEEPS TELLING ME THAT ALL OF THESE ANSWERS ARE WRONG! does anyone else have another way?! i just dont get it...it i tried everything posted here right now..but it still doesnt work! does anyone have any other ans?!
2007-12-07 17:49:46 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The difficulty is the 1/3x^3 term.
Does this mean (1/3) x³ or 1 / (3x³) ?????
You really must use brackets.
Will take a guess and go for (1/3)x³ but it can be no more than a guess.
I = ∫ 8 e^x - 3 x ³ - 2 dx
I = 8 e^x - 3 x^4 / 4 - 2 x + C
2007-12-07 23:38:20 · answer #1 · answered by Como 7 · 4⤊ 0⤋
8 e^x - 9 (1/3x^3) - 2.
the question isnt clear i mean 9(1/3x^3) if u cld clearly type this part then imight be able to help
2007-12-08 02:15:54 · answer #2 · answered by MTG G 2 · 0⤊ 0⤋
The answer is 8e^x - (3/4)*x^4 - 2x
I'm not sure what you are checking it against, if it is the solution in the back of the textbook...well occasionally those are wrong. Is there an answer given?
2007-12-08 01:57:31 · answer #3 · answered by ? 3 · 0⤊ 0⤋