can soemone help me step by step? =)
2007-12-07 17:40:34 · 6 answers · asked by stricking 2 in Science & Mathematics ➔ Mathematics
oops i meant X^4-1 divided by X^2-1
2007-12-07 17:41:19 · update #1
oy, i meant X^2-1/X^4-1 sorry
2007-12-07 18:55:18 · update #2
(x^4-1)/(x^2-1) = (x^2+1)(x^2-1)/(x^2-1) = x^2+1
2007-12-07 17:43:42 · answer #1 · answered by RobertJ 4 · 0⤊ 0⤋
(x^4-1)/(x^2-1)= (x^2+1)(x^2-1)/(x^2-1) = (x^2+1)
2007-12-08 01:55:02 · answer #2 · answered by MTG G 2 · 0⤊ 0⤋
X^4-1 / X^2 -1 Factorise
(X^2-1)(X^2+1) / ( X^2 - 1)
=(X^2 + 1)
2007-12-08 01:48:36 · answer #3 · answered by Murtaza 6 · 0⤊ 0⤋
x ^ 4 - 1 can be broken down to (x ^ 2 + 1 )(x ^ 2 -1)
(x ^ 2 + 1 )(x ^ 2 -1)
--------------------------
(x ^ 2 -1)
The (x ^ 2 -1)'s cancel each other out leaving (x ^ 2 + 1 ) in the numerator.
Your answer is: (x ^ 2 + 1 )
2007-12-08 01:46:08 · answer #4 · answered by Captain Getalife 2 · 0⤊ 0⤋
x^4 – 1 you can see it is subtraction of two squares,
e.g. a^2 – b^2 factors of it are (a + b)(a – b)
How we arrived at this step ?
a^2 – b^2
= a^2 + ab – ab – b^2----adding and subtracting term ab
= a(a + b) – b(a + b)
= (a + b)(a – b)
similarly factors of
x^4 – 1 = (x^)^2 – (1)^2
= (x^2 + 1)(x^2 –1)
= (x^2 + 1)(x +1)(x – 1)
similarly factors of x^2 – 1
(x + 1)(x – 1)
division of two factors
(x^2 + 1)(x +1)(x – 1)/(x +1)(x – 1)
= (x^2 + 1)
2007-12-08 01:53:48 · answer #5 · answered by Pranil 7 · 0⤊ 0⤋
(x^4-1) / (x^2-1)=
(x^2-1)(x^2+1) / (x-1) ( x+1)=
(x-1)(x+1)(x^2+1) / (x-1)(x+1) x-1 's and x+1's cance'
x^2+1
2007-12-08 02:28:52 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋