2007-12-07 17:02:58 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(a^p)(a^q)=a^(p+q)
Use that.
2007-12-07 17:15:26 · answer #1 · answered by gugliamo00 7 · 0⤊ 0⤋
17^(39 + 34 +5)
=17^78
2007-12-07 17:06:27 · answer #2 · answered by Anonymous · 0⤊ 0⤋
17^(39+34+5)=17^78
2007-12-07 21:57:09 · answer #3 · answered by sonali 3 · 0⤊ 0⤋
17^(39 + 34 + 5)
17^(78)
2007-12-07 18:56:50 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
(17^39) x (17^34) x (17^5) = 17^(39 + 34 + 5) = 17^78
2007-12-07 17:06:32 · answer #5 · answered by Northstar 7 · 0⤊ 0⤋
17^(39+34+5)=17^78
2007-12-07 17:06:12 · answer #6 · answered by someone else 7 · 0⤊ 0⤋
a^2 x a^3 = a^(2+3)
is it that hard? really? oh man...
17^39 x 17^34 x 17^5
17^(39+34+5)
figure it out.
2007-12-07 17:06:39 · answer #7 · answered by Anonymous · 0⤊ 0⤋
17^78
2007-12-07 17:09:36 · answer #8 · answered by Rich 7 · 0⤊ 0⤋
GEEK to the 34th power!
2007-12-07 17:10:45 · answer #9 · answered by J F 2 · 0⤊ 0⤋