2007-12-07 16:06:13 · 4 answers · asked by jkf 1 in Science & Mathematics ➔ Mathematics
f `(t) = 4t³ - 5
f `(49) = 4 x 49³ - 5
f `(49) = 470,591
If, perhaps, t = 4.9 answer would be:-
f `(t) = 4 x 4.9³ - 5
f `(t) = 465.5
2007-12-08 02:45:43 · answer #1 · answered by Como 7 · 3⤊ 0⤋
f(t)=t^4-5*t+69 when t=49
relative rate of change of f means
You are asked f'(t=49)
f'(t) = 4t^3 - 5
f'(49) = 470591
2007-12-07 16:11:02 · answer #2 · answered by mlam18 6 · 0⤊ 0⤋
@ first guy who answered.
Its probably not wrong because you
are cubing the # and the # itself happens
to be pretty big.
It seems your answer is reasonable.
But it might be wrong in the context
of the problem/or not
2007-12-07 16:12:07 · answer #3 · answered by sudhi_kandi 3 · 0⤊ 0⤋
4t^3-5
470591
but for some reason this sounds like it could be wrong
2007-12-07 16:10:14 · answer #4 · answered by Jimmy Mills 2 · 0⤊ 0⤋