I've been asked to graph the expression y =5x -5. I checked some old algebra books and am not sure what I am doing here.
The link is to the template I was given. Any help would be great. Thanks in advance.
http://i143.photobucket.com/albums/r152/benspargur/graph2.jpg
2007-12-07 15:42:46 · 4 answers · asked by Superman 2 in Science & Mathematics ➔ Mathematics
y=mx+b
m=slope ; fine whats equivalent to 5.
use rise over run
ex. 5/1=5, -5/-1=5 then you get the line
b= y-intercept ; graph the y-intercept.
http://i17.tinypic.com/864t0kx.jpg
2007-12-07 15:57:57 · answer #1 · answered by Anonymous · 0⤊ 0⤋
At the y intercept, x=0 So substitute into equation y intercept = 5*0 - 5 = 0 - 5 = -5
2016-05-22 02:50:13 · answer #2 · answered by myung 3 · 0⤊ 0⤋
So let's start from the top.
You have: y=5x-5.
The -5 will have a point on the y axis (veritcal line)
So from that point which is (0,-5),
you will move up 5, and 1 over to the right (slope).
Plug in your point and connect the 2 points.
Hope that helps!
2007-12-07 15:53:05 · answer #3 · answered by Kat 2 · 0⤊ 0⤋
A line requires a minimum of 2 points.
(0 , - 5) , (4 , 15) are two suitable points.
Draw line thro` these points.
2007-12-08 03:34:38 · answer #4 · answered by Como 7 · 2⤊ 0⤋