find dy/dx for y = 1/x^7?

4 ⤊

2007-12-07 14:17:23 · 4 answers · asked by jiles357 1 in Science & Mathematics ➔ Mathematics

y = x^(- 7)
dy/dx = (- 7) x^( - 8 )
dy/dx = (- 7) / x^8

2007-12-08 03:04:49 · answer #1 · answered by Como 7 · 3⤊ 0⤋

1/x^7 = x^(-7)

so dy/dx = -7 * x^(-8) = -7 / x^8

2007-12-07 22:20:32 · answer #2 · answered by Chris W 4 · 0⤊ 1⤋

Rewrite this using a negative exponent:

y = x^(-7)

now use the power rule:

y' = -7x^(-8)

that's it! :)

2007-12-07 22:20:50 · answer #3 · answered by Marley K 7 · 0⤊ 1⤋

stop trying to cheat on your home work

2007-12-07 22:20:06 · answer #4 · answered by Daniel G Brown 2 · 1⤊ 1⤋