PLease help out...
2007-12-07 08:47:26 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You'd apply the rules to the " ^2 " part first, and then use the chain rule for the sine function:
2sin(x) * cos(x)
Feel free to email me for any clarifications.
2007-12-07 08:50:33 · answer #1 · answered by Bugmän 4 · 0⤊ 0⤋
The answer is 2 sin(x) * cos(x)
because 2sin(x) * d/dx sin(x)
=2 sinx*cosx
all you do is bring the power down in front of sin then find the derivative of the inside function in this case its sin and multiply them together. Or use a calculator. Hope this helps
2007-12-07 16:58:05 · answer #2 · answered by Brenda N 2 · 0⤊ 0⤋
Use the chain rule to get 2 sin x cos x = sin 2x.
2007-12-07 16:57:18 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
sin²x = sin x * sin x
Use the product rule
d/dx = sin x cos x + sin x cos x = 2 sin x cos x
2007-12-07 16:53:54 · answer #4 · answered by Joe L 5 · 0⤊ 0⤋
sin^2 x = sin x * sin x ( use product rule)
= d/dx sin x * sinx + d/dx sin x * sin x
= cos x sin x + cos x sin x
= 2sin x cosx
2007-12-07 17:36:24 · answer #5 · answered by james w 5 · 0⤊ 0⤋
Sin^2 x
By using power rule,
2Sin x d/dx (Sin x)
2Sin x . Cos x
2Sin xCos x.
2007-12-07 16:57:40 · answer #6 · answered by Usman Ashraf 1 · 0⤊ 0⤋
If you change it to (sinx)(sinx) then use the product rule you should get it.
Also the chain rule would work.
and f'(sinx) = Cosx, if you didnt know.
2007-12-07 16:50:10 · answer #7 · answered by Anonymous · 0⤊ 1⤋
(sin^2 x)'= 2sinx*cosx = sin(2x)
2007-12-07 16:55:47 · answer #8 · answered by Vlad N 2 · 0⤊ 0⤋
(sinx)^2= 2sinxcosx
2007-12-07 17:02:07 · answer #9 · answered by wouldn't-u-like-to-know ;] 3 · 0⤊ 0⤋
2sinxcosx
you should use parenthesis so as not to confuse
2007-12-07 16:50:34 · answer #10 · answered by KEYNARDO 5 · 0⤊ 0⤋