is it going to be past people, too?
like lita and trish?
PLEASE, please at least say lita and trish
2007-12-07 08:19:30 · 11 answers · asked by georgia jay (: 2 in Sports ➔ Wrestling
Lita and Trish will make appearances, one night only though.
2007-12-07 08:22:05 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Yes trish & lita will be there but im going to watch it for Stone Cold Steve Austin
2007-12-07 08:56:18 · answer #2 · answered by Hector C 1 · 0⤊ 1⤋
Yes Yes, Lita is going to be there and so is trish...go to wwe.com for more information wwe 15th anniversary..
all the others like, eric bishoff, stone cold, mic foley, hulk hogan, and many more!
WOOOOOOOOOOOOOOOOOOOOOOOOOOOO!
P.S- Evolution returns also!
2007-12-07 08:56:43 · answer #3 · answered by Chainstein™ has finally returned 6 · 1⤊ 1⤋
Trish, Eric bischoff, Undertaker, The Rock, Y2J, Evolution, Hogan, Mick foley , stone cold will be there and this person i never heard of named sunny
2007-12-07 10:17:16 · answer #4 · answered by Anonymous · 0⤊ 1⤋
Trish, Eric bischoff, Undertaker, The Rock, Y2J, Evolution, Hogan, Mick foley and best of all, stone cold will be there..
2007-12-07 08:22:20 · answer #5 · answered by Mr DEDEDE aka The Gawd 4 · 0⤊ 1⤋
most of the past wrestlers will make an apperance to include Trish
Stone Cold
have yewt to here anything about Lita but i bet she will
2007-12-07 09:18:23 · answer #6 · answered by nas88car300 7 · 0⤊ 1⤋
lita and trish r going to be there and if i am wrong u can go to wwe.com they might say wats going to happen
2007-12-07 08:24:33 · answer #7 · answered by ? 2 · 0⤊ 1⤋
hulk hogan, stone cold, lita, trish, dusty rhodes maybe.
2007-12-07 10:17:29 · answer #8 · answered by abby*rose<3 1 · 0⤊ 1⤋
There will be one other person on the show and that is Sunny.
I'm sure there will be more but so far Sunny and the names other people mentioned are all that have been confirmed.
2007-12-07 09:07:39 · answer #9 · answered by komets.geo 7 · 0⤊ 1⤋
dont know
but the rock declinded the invite :(
2007-12-07 08:24:14 · answer #10 · answered by Anonymous · 1⤊ 0⤋