A solution contains 0.837M Li^+ and 7.32 X 10^-2M CO3^-2. What type of solution is this with respect to lithium Carbonate? Compare your Q and K. (Ksp=1.70 X 10^-3)
a. saturated
b. unsaturaed
c. supersaturated
can someone please help me answer this question? and show the answer is reached.
thank you
2007-12-07 08:07:46 · 2 answers · asked by abc 1 in Science & Mathematics ➔ Chemistry
Lithium carbonate has the formula Li2CO3. So, the formula for Ksp is:
Ksp = [Li]^2 [CO3-]
The ion product (Q) is calculated from that same formula using the concentrations of each ion given in the problem:
Q = 0.837^2 X 7.32 X 10^-2 = 0.0512
Since the value of Q is greater than the Ksp for this compound, the solution is supersaturated.
A saturated solution will have an ion product equal to Ksp, and an unsaturated solution will have a Q less than Ksp.
2007-12-07 08:28:30 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋
1.70*10^-3=c(Li^+)^2*c(CO3^2-)
c(Li^+)=2*c(CO3^2-) in saturated solution
1.70*10^-3=c(Li^+)^3
[1.70*10^-3]^(1/3)=c(Li^+)
0.1193mol/L=c(Li^+) in saturated solution
0.0596mol/L=c(CO3^2-)in saturated solution
these values are greater than the concentration of the solution and therefore answer b is correct unsaturated.
2007-12-07 16:22:41 · answer #2 · answered by klimbim 4 · 0⤊ 0⤋