how do i solve (x+1)(x^2-x+1)?

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how do i solve (x+1)(x^2-x+1)?

2007-12-07 07:20:16 · 3 answers · asked by Ryan E 1 in Science & Mathematics ➔ Mathematics

3 answers

just solve for x
x + 1 = 0
x = -1
x^2 - x + 1 = 0
This you need to put in the quadratic equation
-(-1) +- (sqrt((-1)^2 - 4(1)(1)))/2(1)
1 +- sqrt(1 - 4)/2
1 +- sqrt(-3)/2
So you get 1 + sqrt(-3)/2 and 1 - sqrt(-3)/2
So those are all your possible answers for x

2007-12-07 07:26:40 · answer #1 · answered by Jamanski 3 · 0⤊ 0⤋

x^3-x^2+x+x^2-x+1= x^3+1

2007-12-07 15:24:33 · answer #2 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋

(x+1)(x^2-x+1)
first multiply everything by x and then by +1 so
x^3-x^2+x+x^2-x+1
then simplify
x^3+1

2007-12-07 15:26:53 · answer #3 · answered by J D 5 · 0⤊ 0⤋