electric force? gravitational force?

Question

2 objects one with as mass 0f 10 kg and the other with 17kg each with a charge of -.013C. separated by 9 m

what is the electric force they exert on each other?
gravitational force?

Answer 1

Gravitational force = Gm1m2/r²
Gravitational force = (6.67*10^-11)(17)(10)/(9)²
Gravitational force = 1.399876543*10^-10 N.

Electric force = k (Q1Q2)/r²
Electric force = (8.988*10^9)(-0.13)(-0.13)/(9)²
Electric force = 18755274.074 Nts

Answer 2

The 4 fundamental forces of nature are: Electromagnetic force, Gravitational force, Strong nuclear force and weak nuclear force. All other forces derive from these 4. The strongest is the Strong nuclear force, followed by the Electromagnetic force, followed by the Weak nuclear force and last but not least the Gravitational force.

Answer 3

M1=10 kg Q1 = -0.13 C
M2=17kg Q2 = -0.13 C
D = 9 m

The electric force is given by Coulomb law:

Felectric = k*Q1*Q2 / (r^2) where k = 9 10^9 N m^2 / C^2 (you can fine this values on the website and also how it is obtained)
(http://hyperphysics.phy-astr.gsu.edu/HBASE/hframe.html )

Felectric = 0.13*0.13 * 9 10^9 / 81 = 1.8778 10^6 N (Newton)


The gravitational force is given by gravity law:

Fgravity = G*M1*M2 / (r^2) where G = 6.67 10^(-11) N m^2 / (kg^2) (you can fine this values on the website and also how it is obtained)

(http://hyperphysics.phy-astr.gsu.edu/HBASE/hframe.html)



Fgravity = 10*17*6.67 10^(-11) / 81 = 13.999 10^(-11) N

Answer 4

Not sure how to find electric force, but for the gravitational force:

F=(GM1M2)/R^2 where G is the gravitational constant.
F=(6.67428e-11)(17)(10)/(81) = 1.400e-10

Answer 5

Force of gravity = Fg = -GM1*M2/r^2

Fg = -6.67*10^-11*10*17/(9^2) = -1.4*10^-11 Nts

The "-" sign means the force is attracitve.

Force of electric field = Fe = k*Q1*Q2/r^2

k = 9 x10^9 Nt-m^2/Coul^2

Fe = 9x10^9*(-0.13)*(-0.13)/9^2 =1.88x10^6 Nts

This is a repulsive force - the sign is positive. (Like charges repel)