4x-12 / x^2+6x * 5x / 3-x
2007-12-07 06:52:52 · 4 answers · asked by God Bless America!~ 4 in Science & Mathematics ➔ Mathematics
4x-12 / x^2+6x * 5x / 3-x
( 4x - 12 ) ( 5x ) / ( x^2 + 6x ) ( 3 - x )
( 20x^2 - 60x ) / ( 3x^2 + 18x - x^3 - 6x^2 )
-20x ( x - 3 ) / ( x^3 + 3x^2 - 18x )
-20 x ( x - 3 ) / x ( x^2 + 3x -18 )
-20 ( x - 3 ) / ( x +6 ) ( x -3 )
-20 / ( x + 6 )
2007-12-07 07:00:49 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
[(4x -- 12) / (x^2 + 6x)]*[5x /(3 -- x)]
= 4(x -- 3)*5x / x(x + 6)(x -- 3) as A / B * C / D = A*C / B*D
now cancelling x(x -- 3) from numerator and denominator both
= -- 20 / (x + 6) as (x -- 3) / (3 -- x) = -- 1
2007-12-07 15:10:03 · answer #2 · answered by sv 7 · 0⤊ 0⤋
4x-12 / x^2+6x * 5x / 3-x
not another without brackets ..... declined
2007-12-07 15:40:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
4x-12 5x
----------------------------
x^2+6x 3-x
4(x-3) 5x
-------------------------
x(x+6) 3-x
4 5x
--------------------------
x(x+6)
20 / (x+6)
2007-12-07 15:15:47 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋