math help please?

Question

write in simplest form.

1. x^2+6x-16 / x^2-64




2. 48a^5b / 12ab^2

Answer 1

(x² + 6x - 16) / (x² - 64) =
[ (x + 8)(x - 2)] / [(x + 8)(x - 8)] =
(x - 2) / (x - 8)

(48a^5b) / (12ab²) =
(48/12)(a^5/a)(b/b²) =
4a^4 / b

break polynomials down into factors, and look at monomials one kind of factor at a time.

Answer 2

1) You are going to factorise
(x-2)(x+8) / (x-8)(x+8)
=(x-2) / (x-8)


2)48a^5b / 12ab^2

Look first 48/12 = 4
then a^5 / a = a^4
b/b^2 = 1/b

=4a^4/b

Answer 3

1. x^2+6x-16 / x^2-64

(x-2) (x+8) / (x-8) (x+8) = (x-2)/(x-8)


2. 48a^5b / 12ab^2

= 4a^4/b


KIS (Keeping it simple)

Answer 4

1. you'd factor the numerator into (x+8)(x-2)
then you'd factor the denomanator into (x-8)(x+8)
so then you could cross out (x+8) in the numerator and
denomonator to get (x+2)/(x-8)

2. 48/ 12=4
a^5/a. so 5-1 = 4. a^4
b/b^2 so there's a b in the denomanotor
=> 4a^4 / b

Answer 5

x^2+6x-16 / x^2-64

( x + 8 ) ( x - 2 ) / ( x + 8 ) ( x - 8 )
( x - 2 ) / ( x - 8 )

48a^5b / 12ab^2

4a^3 / b

Answer 6

1. Factor the top and bottom then reduce:

(x+8)(x-2) (x-2)
------------- = -------
(x+8)(x+8) (x+8)

2. Can be reduced simply.
48 and 12 reduces to 4 and 1
a^5 and a reduces to a^4 and 1
b and b^2 reduces to 1 and b
So the answer is

4a^4 / b

Answer 7

(x+8)(x-2)/ (X-8)(x+8)= x-2/x-8

4a^4/ b

Answer 8

4a^ 5/b