Exponents need help?

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1. (x/y)^5 ( 2/x)^4 (y/4)^3

2.(5^3 + 3^5)^0 / 2^-1

2007-12-07 06:04:39 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

1. (x/y)^5 ( 2/x)^4 (y/4)^3
= [ 16 x^5 y^3 ] / [ 64 x^4 y^5 ]
= x / 4y^2

2.(5^3 + 3^5)^0 / 2^-1
= 1/ (!/2)
= 2

2007-12-07 06:08:06 · answer #1 · answered by harry m 6 · 0⤊ 0⤋

1) (x/y)^5 (2^4 x^-4(y/4)^3= x^5*y^-5*2^4 x^-4* y^3 4^-3
=(x/y^2)2^4* 4^-3
=x/4y^2
and the next one in the same way.

2007-12-07 14:29:02 · answer #2 · answered by anordtug 6 · 0⤊ 0⤋

(x/y)^5 ( 2/x)^4 (y/4)^3
=x^(5-4) * Y^(-5+3) * 2^(4-6)
=x/y^2 * 2^(-2)
=x/(y^2) * (1/4)
=0.25 * x/(y^2)

2007-12-07 14:11:22 · answer #3 · answered by shanu_gupta2003 2 · 0⤊ 0⤋