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2007-12-07 06:00:08 · 5 answers · asked by Timothy M 1 in Science & Mathematics Mathematics

5 answers

Think of it this way... you can include each element, or exclude it. 2 choices for each element.

2 x 2 x 2 = 8 ways.

In general, a set with n elements can form 2^n different subsets. Of course that includes the empty set, so if you need subsets with at least one element, the answer is 2^n - 1.

0 elements:
{ }
1 element:
{0}, {2}, {4}
2 elements:
{0,2}, {0, 4}, {2, 4}
3 elements:
{0, 2, 4}

Total of 8 subsets.

2007-12-07 06:04:44 · answer #1 · answered by Puzzling 7 · 0 0

3

2007-12-07 06:02:33 · answer #2 · answered by Latex 3 · 0 1

Well, they are Ø, { 0 }, { 2 }, { 4 }, { 0, 2 }, { 0 , 4 }, { 2, 4 }, and { 0, 2, 4 } for a total of eight (seven of which are proper subsets).

2007-12-07 06:02:56 · answer #3 · answered by jgoulden 7 · 1 0

2^3 or 8.
Possible subsets are
{null},{0},{2},{4},{0,2},{0,4},{2,4},{0,2,4}

2007-12-07 06:03:32 · answer #4 · answered by guenthercorp 3 · 0 0

there are 8 subsets
0
2
4
0,2,4
0,2
0,4
2,4
and empty set

10 pts

2007-12-07 06:03:20 · answer #5 · answered by Anonymous · 0 0

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