Think of it this way... you can include each element, or exclude it. 2 choices for each element.
2 x 2 x 2 = 8 ways.
In general, a set with n elements can form 2^n different subsets. Of course that includes the empty set, so if you need subsets with at least one element, the answer is 2^n - 1.
0 elements:
{ }
1 element:
{0}, {2}, {4}
2 elements:
{0,2}, {0, 4}, {2, 4}
3 elements:
{0, 2, 4}
Total of 8 subsets.
2007-12-07 06:04:44
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answer #1
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answered by Puzzling 7
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3
2007-12-07 06:02:33
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answer #2
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answered by Latex 3
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Well, they are Ã, { 0 }, { 2 }, { 4 }, { 0, 2 }, { 0 , 4 }, { 2, 4 }, and { 0, 2, 4 } for a total of eight (seven of which are proper subsets).
2007-12-07 06:02:56
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answer #3
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answered by jgoulden 7
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2^3 or 8.
Possible subsets are
{null},{0},{2},{4},{0,2},{0,4},{2,4},{0,2,4}
2007-12-07 06:03:32
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answer #4
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answered by guenthercorp 3
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there are 8 subsets
0
2
4
0,2,4
0,2
0,4
2,4
and empty set
10 pts
2007-12-07 06:03:20
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answer #5
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answered by Anonymous
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