The perimeter of a retanguler is 24. If the width is 4, what is the area?? Explain your answer in details??
2007-12-07 05:43:02 · 7 answers · asked by Kitana100 1 in Science & Mathematics ➔ Mathematics
The perimeter of a rectangle is 4 sides added up.
2 of those sides are the width and 2 are the length.
W + W + L + L = Perimeter
==> 2W + 2L = P
Since we know the perimeter is 24
2W + 2L = 24
Since we know the width is 4
2(4) + 2L = 24
==> 8 + 2L = 24
Now subtract that 8 from both sides to leave the variable on th e left
2L = 24 - 8
==> 2L = 16
Divide both sides by 2
==>L = 8
so the length is 8
.
Now to find the area, multiply length times width.
8 * 4 = 32 in²
2007-12-07 05:46:24 · answer #1 · answered by Jeƒƒ Lebowski 6 · 1⤊ 0⤋
The area is 32 because if the width is 4 that means that u add 4 and 4 to get 8. Then you do 24-8=16, then divide by two to get 8. So then 8+8+4+4=24, Thus the length equals 8. So 8x4=32.
2007-12-07 13:50:01 · answer #2 · answered by Bennyboxer 3 · 0⤊ 0⤋
24=(4*2)+2y
4= width
2y=2sides of length
4*2=perimeter of widths added
so
24=8+2y
solve for y
24-8=2y
16/2=y
8=y
width x length = area
4*8=area
=32
2007-12-07 13:50:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The area is 32.
2007-12-07 13:47:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋
4+4+8+8=24
4x8=32
Area=32
2007-12-07 13:46:58 · answer #5 · answered by Mick 1 · 0⤊ 0⤋
P = 2L + 2W
24 = 2L + 2(4)
24 = 2L + 8
16 = 2L
8 = L
A = LW = 8(4) = 32
and it's RECTANGLE, not retanguler.
2007-12-07 13:48:46 · answer #6 · answered by Philo 7 · 1⤊ 0⤋
P = 2L + 2W = 24
W = 4
so
2L + 2 ( 4 ) = 24
2L + 8 = 24
2L = 16
L = 8
2007-12-07 13:47:08 · answer #7 · answered by jgoulden 7 · 0⤊ 0⤋