Chien-Ming Wang and Melky Cabrera for Johan Santana
2007-12-07 05:15:08 · 13 answers · asked by Anonymous in Sports ➔ Baseball
Season Season
Wang 2006:19-6 Wang 2007:19-7
Santana 2006: 19-6 Santana 2007:16-13
2006 Playoffs 2007 Playoffs
Wang 1-0 Wang 0-2
Santana 0-1 Santana (Watching M*A*S*H reruns, Stats not available)
-Wang and Melky make the league minimum- which means hundreds of thousands, not millions (Not Too Expensive)
Not worth the HYPE Red Sox can get him so we can see him pull a Gagne... In other words Santana is not worth it.
2007-12-07 05:28:31 · answer #1 · answered by Anonymous · 3⤊ 4⤋
Never Happen. Wang although very good is coming into a Arbitration year and could get big dollars. The Twinkies are looking to get something not expensive for Johan. One of the Kids would be a great Payroll addition.
2007-12-07 13:45:06 · answer #2 · answered by Oz 7 · 1⤊ 1⤋
No, simply because Wang's value decreases going to a ballpark with a turf field. You can see it in his stats now on the road in such ballparks. Wang is also older and closer to arbitration.
2007-12-07 15:52:08 · answer #3 · answered by Anonymous · 2⤊ 0⤋
are you high?!?!?! I would have only done either hughes or kennedy, and cabrera, definitely not Wang. He is our ace even if we had sanatana
2007-12-07 14:45:08 · answer #4 · answered by michael p 3 · 1⤊ 2⤋
That's a crappy return for Johan Santana. Yankees will have to offer way more than that.
2007-12-07 13:23:47 · answer #5 · answered by D.I.L.L.I.G.A.F. 3 · 4⤊ 5⤋
TWINS WON'T DO IT SINCE WANG IS COMING OFF TWO
SEASONS IN WHICH HE WON NINETEEN GAMES & IS SOON ARBITRATION ELIGIBLE.
2007-12-07 13:20:54 · answer #6 · answered by Anonymous · 4⤊ 0⤋
Not a good trade.
2007-12-07 18:58:25 · answer #7 · answered by Anonymous · 0⤊ 0⤋
I don't think the Twins would accept it but I'd probably make it.
2007-12-07 13:31:50 · answer #8 · answered by Anthony D 3 · 1⤊ 3⤋
No
2007-12-08 05:52:23 · answer #9 · answered by Go For Broke 3 · 0⤊ 0⤋
Give me a break!!!!
2007-12-07 14:33:03 · answer #10 · answered by halfwaytoeverywhere 5 · 1⤊ 2⤋