2007-12-07 03:25:32 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
9 = 3 x 3
11 = 11 * 1
15 = 3 * 55
LCM = 3 x 3 x 11 x 5 = 495
2007-12-07 03:29:56 · answer #1 · answered by Anonymous · 0⤊ 0⤋
9 = 3 * 3
11 = 11 [since 11 is a prime no.]
15 = 3 * 5
LCM = 3 x 3 x 11 x 5 = 495
2007-12-09 10:31:09 · answer #2 · answered by Anonymous · 0⤊ 0⤋
3 x 3 x 11 x 5 = 495
2007-12-09 01:45:55 · answer #3 · answered by m!l@ 2 · 0⤊ 0⤋
Look at their prime factorizations
9 = 3 x 3
11 = 11
15 = 3 x 5
So their LCM is
3 x 3 x 5 x 11 = 495
2007-12-07 11:31:01 · answer #4 · answered by jgoulden 7 · 0⤊ 0⤋
LCM = 11 * 3^2 *5 = 495
2007-12-07 11:29:00 · answer #5 · answered by sahsjing 7 · 0⤊ 0⤋
Prime factor first -
9 = 3*3
11 -prime
15 = 5*3
Now make a list of the primes that can yield all three -
3, 3, 11, and 5
(since "3" appears in both 9 and 15, you don't need a third "3")
now multiply -
3 * 3 * 11 * 5 = ???
That is the least common multiple.
2007-12-07 11:32:33 · answer #6 · answered by Gary H 6 · 1⤊ 0⤋