V = 20√(C + 273) relates speed of sound, V, in meters per second, to air temp, C, in degrees Celsius. What is the temp, in degrees Celcsius, when the speed of sound is 320 meters per second?
Do you just plug in the 320? What answer did you get, and how did you do it?
2007-12-07 03:13:01 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(v / 20) = √(c + 273)
v ² / 400 = c + 273
c = v ² / 400 - 273
c = 320 ² / 400 - 273
c = - 17° C
2007-12-07 03:26:03 · answer #1 · answered by Como 7 · 3⤊ 0⤋
V = 20√(C + 273)
if V = 320 m/s
320 = 20√(C + 273)
divide both sides of the equation by 20 to get
320/20 = √(C + 273)
16 = √(C + 273)
square both sides to get
16^2 = C +273
256 = C +273
substract 273 from both sides of the equation to get
256 -273 = C
-17 = C
C = -17 degrees Celsius
2007-12-07 03:22:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Let V = 320 and solve for C. You should get C = -17.
2007-12-07 03:18:51 · answer #3 · answered by Anonymous · 0⤊ 0⤋