how do you solve (a+b)^5 ?

Question

how do you use Pascal's Triangle to solve this?

Answer 1

http://www.lincoln.k12.nv.us/alamo/high/Departments/Math/Pascal/ptreal1r.gif

1 5 10 10 5 1

a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5

Answer 2

^^^This guy explained it better than me^^^


Pascals Triangle goes like this

1st power 1 1
2nd power 1 2 1
3rd power 1 3 3 1
4th power 1 4 6 4 1
5th power 1 5 10 10 5 1

Answer 3

Build the triangle
........................1
....................1...2...1
.................1....3...3...1
...............1...4....6...4..1
..............1..5..10. 10.5..1... these are the coeff of each term

then write a^5+5a^4b+10a^3b^2+10a^2b^3+5ab^4+b^5

notice the order of a goes down and b does up, total 5 in each term.