At a temperature of ____ C , 0.444 mol of CO gas occupies 11.8 L at 889 torr?

3 ⤊

At a temperature of ____ C , 0.444 mol of CO gas occupies 11.8 L at 889 torr?

2007-12-07 02:49:30 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

you have pV=nRT
889 torrs = 101325*889/760 =118524 Pa
V= 11.8*10^-3 m^3

with the formula T = pV/nR

T= 118524*11.8*10^-3/0.444*8.314=378.8°K
and in celsius 378.8-273=105.8C

2007-12-07 02:58:20 · answer #1 · answered by maussy 7 · 0⤊ 1⤋

ideal gas law is: PV = nRT
P = pressure (torr) = 889 torr
V = volume (Liters) = 11.8 L
n = moles of gas = 0.444 mol
R = gas constant = 62.4 (L * torr / mol * k)

solve for T (in kelvin)

T = PV/nR
T = (889*11.8)/(.444*62.4)
T = 378.6 K
convert to C (subtract 273)
T = 105.6 deg C

2007-12-07 02:56:31 · answer #2 · answered by shadowsjc 2 · 3⤊ 1⤋