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this is a simultenous equation
4x+2y=5
3x-4y=1

2007-12-07 01:16:11 · 9 answers · asked by Spicy_dymples 1 in Science & Mathematics Mathematics

9 answers

Multiply the first equation by 2 and add the equations.
Solve for x and then substitute the value of x in any equation to get the value of y.

Good Luck

2007-12-07 01:21:36 · answer #1 · answered by Anonymous · 0 2

Elimination By addition Method

4x + 2y = 5- - - - -Equation 1
3x - 4y = 1- - - - - Equation 2
- - - - - - - - -

Multiply equation 1 by 2

4x + 2y = 5

2(4x) + 2(2y) = 2(5)

8x + 4y = 10

Combine this equation with equation 2
- - - - - - - - - -

Elimination of y

8x + 4y = 10
3x - 4y = 1
- - - - - - - - - -

11x = 11

Divide both sides of the equation by 11

11x / 11 = 11 / 11

x = 11/11

x = 1

Substitute the x value into equation 1
- - - - - - - - -

4x + 2y = 5

4(1) + 2y = 5

4 + 2y = 5

Transpose 4

4 + 2y - 4 = 5 - 4

2y = 1

Divide both sides of the equation by 2

2y / 2 = 1 / 2

y = 1/2

Substitute the y value into equation 1
- - - - - - - - - -

Check for equation 1

4x + 2y = 5

4(1) + 2(1/2) = 5

4 + 2/2 = 5

4 + 1 = 5

5 = 5

- - - - - - - - -

Check for equation 2

3x - 4y = 1

3(1) - 4(1/2) = 1

3 - 4/2 = 1

3 - 2 = 1

1 = 1

- - - - - - - - -

Both equations balance

The solution set (1, 1/2)

- - - - - - - -s-

2007-12-07 01:34:39 · answer #2 · answered by SAMUEL D 7 · 3 1

one million.(c) x^2 + 3x + 2 [ as (x +a)(x + b) = x^2 + (a + b)x + ab ] 2.(a) 2x^2 + 5x - 12 [as (2x - 3)(x + 4) = 2x (x + 4) -3(x + 4) = 2x^2 + 8x -3x - 12 3.(a) y^2 - 4 [ as (a - b) (a + b) = a^2 - b^2 ] 4.(b) 8y^2 - 18y - 5 [as (4y + one million)(2y - 5) = 4y(2y - 5) +one million(2y - 5) = 8y^2 -20y + 2y - 5 ] 5.(b) x^2 + 6x + 9 [ as (a + b)(a + b) = a^2 + 2ab + b^2 ]

2016-10-10 11:21:20 · answer #3 · answered by ? 4 · 0 0

4x+2y=5
3x-4y=1

you can solve it by elimination:

(4x+2y=5) 2 --- so that you can cancel something
3x-4y=1

8x +4y = 10,..... ------- cancel 4y and -4 because
+ 3x - 4y = 1 ,.....;....-------4y -4y = 0

11x = 11
x = 1

solve for y
3x-4y = 1
3(1)-4y =1
3 - 4y = 1
-4y = 1 - 3
-4y =-2
y = 1/2


therefore the value pf x is 1 and the value of y is 1/2

2007-12-07 01:28:11 · answer #4 · answered by xleryy 2 · 0 3

4x+2y=5
3x-4y=1

multiply the first quation by 2
(4x+2y=5)*2
8x+4y=10

now add this equation 1 with equation 2
8x+4y=10
3x-4y=1
--------------------
11x+0y=11
11x=11
x=11/11
x=1

now substutite this value of x in equation 1
4x+2y=5
4*1+2y=5
4+2y=5
2y=5-4
2y=1
y=1/2

2007-12-07 01:22:22 · answer #5 · answered by Siva 5 · 0 2

8x + 4y = 10
3x - 4y = 1------ADD

11x = 11
x = 1

4 + 2y = 5
2y = 1
y = 1/2

x = 1 , y = 1/2

2007-12-07 01:22:39 · answer #6 · answered by Como 7 · 3 1

8x + 4y = 10
3x - 4y = 1
------------------
11x = 11
x=1
then 3 - 4y = 1
-4y = -2
y = 1/2

Yep! Do your OWN homework, kid! This was easy enough for someone as dumb as I to type it out.

2007-12-07 01:21:55 · answer #7 · answered by ? 6 · 0 1

4x+2y=5.......(a)

3x-4y=1........(b)

by Eliminating (a) and (b)...

4x+2y=5 *2
3x-4y=1 *1
-----------------+

8x+4y=10
3x-4y=1
-----------------+
11x=11
x=1
then u'll get y=-1/2

2007-12-07 01:37:06 · answer #8 · answered by Anonymous · 0 3

Do your own homework. Its really not that hard.

2007-12-07 01:28:01 · answer #9 · answered by squidge 4 · 1 2

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