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Hey can anyone help me out with this question please??

Use five terms in a power series to estimate:
Integral 0 to 0.2 of (arctan(t^(2)))/(t) dt
(the arctan is in the top of the fraction not preceding it)

Please help!!

2007-12-07 00:15:27 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Arctan z= = z-z^3/3+z^5/5-z^7/7
z=t^2
Arctan t^2 /t = t-t^5/3+t^9/5-t^13/7
The integral from o to0.2 is

(0.2)^2/2 -(0.2)^6/18+(0.2)^10)/50-(0.2)^14/98
You can do the numbers

2007-12-07 00:35:10 · answer #1 · answered by santmann2002 7 · 0 0

Answer is in my link below , at the bottom

http://answers.yahoo.com/question/index;_ylt=AvvWBZA1Fx5K8e3xJ.9Hka7ty6IX;_ylv=3?qid=20071205185017AAb9YP8&show=7#profile-info-IDabPOsQaa

2007-12-07 00:21:33 · answer #2 · answered by Any day 6 · 0 0

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