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my ordered pairs don't work in graphing this linear equation.

2007-12-06 23:37:32 · 6 answers · asked by peaches 1 in Science & Mathematics Mathematics

6 answers

5y = x + 8
Points (2,2) , (12 , 4) lie on line
Draw line thro` these points.

2007-12-07 01:14:05 · answer #1 · answered by Como 7 · 2 0

first make it into a y=mx+b equation. So in this case,
-5y+x=-8
then make all the numbers positive by reversing
5y-x=8
then reduce
y-1/5x=5/8
then I'd plug in some numbers like -1, 0, and 1 and use them to graph the equation.

2007-12-06 23:46:49 · answer #2 · answered by I love the Beatles 2 · 0 0

You need to sub in x=0 to find y
-(0)=-5y+8
-8=-5y
y=1.6
Hence, the line hits y at 1.6, the point (0,1.6)
Sub in y=0 to find x
-x=-5(0)+8
-x=0+8
-x=8
x= -8
Hence the line hits x at -8, the point (-8,0)
Then just connect the points!!!

Hope that helps!!

2007-12-06 23:47:27 · answer #3 · answered by LC 4 · 0 0

Any line can be drawn by connecting two points.

So to find the first point set x=0 and solve for y. That'll give you your first point (0,y)

Then set y=0 and solve for x. That'll give you your second point (x,0).

Connect the dots..... you have now drawn a line using the equation -x= -5y+8

2007-12-06 23:49:50 · answer #4 · answered by Ben B 4 · 0 0

-x = -5y + 8
5y - x = 8
5y = x + 8
y = (1/5)x + (8/5)

slope = 1/5
y-intercept = (8/5) = 1.6

(-8/5) = (1/5)x
-8 = x

x-intercept -8

connect (0,1.6) and (-8,0)

2007-12-06 23:44:33 · answer #5 · answered by Dino 3 · 0 0

well u can find x and y intrcepts, plot, then draw line through
them.

2007-12-06 23:42:00 · answer #6 · answered by ViewtifulJoe 4 · 0 0

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