If f(x)= x + (x)^(1/3) then f ' (x) =?

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please write the full answer!

2007-12-06 22:00:21 · 4 answers · asked by Peyman 2 in Science & Mathematics ➔ Mathematics

As we know that x^n differentiation is n*x^(n-1)
therefore f'(x) = 1 + (1/3)*x^(-2/3)

2007-12-06 22:21:08 · answer #1 · answered by kartheek 2 · 0⤊ 0⤋

f(x)= x + (x)^(1/3)
f ' (x)= 1 + 1/3 x^(-2/3)

2007-12-06 22:09:27 · answer #2 · answered by CPUcate 6 · 0⤊ 0⤋

the answer is

1 + (1/3)x^(-2/3)

2007-12-06 22:05:19 · answer #3 · answered by Sid 3 · 0⤊ 0⤋

f'(x) = 1 + (1/3)*x^(-2/3)

You need only use the power rule on each term

2007-12-06 22:03:54 · answer #4 · answered by Demiurge42 7 · 0⤊ 0⤋