I have a hard time understanding how to start and solve this problem....
Q: Write the nuclear reaction equations for the neutron-induced fission of U-235 to form Xe-144 and Sr-90. How many neutrons are formed in the reaction?
2007-12-06 20:48:46 · 5 answers · asked by ecstyle483 1 in Science & Mathematics ➔ Chemistry
U235 + n ----> Xe144 + Sr90 + 2n
See only one neutron can cause fission in U235. So, the total number of neutrons will be 236. So, the number of neutrons released will be 236 - 234 = 2
There are some other reactions where you get different fission fragments and get 3 neutrons. The average yield is 2.3 or so.
2007-12-06 20:54:29 · answer #1 · answered by Swamy 7 · 8⤊ 0⤋
Induced Fission
2016-11-12 03:47:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
a) Not spontaneous, like some atoms do. Neutron or energy bombardment is not needed to induce fission. b) I'm not quite sure about the 2nd one, but nuclear fusion is more common (i.e. the hydrogen-->helium reactions in the sun, reactions that occur in nuclear reactors/generators) Hope this helps!
2016-04-07 23:21:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
144 + 90 = 234
234 + 1 = 235
2007-12-06 20:53:24 · answer #4 · answered by atheistforthebirthofjesus 6 · 0⤊ 2⤋
are you in power school? the physicist above is correct.
2007-12-07 14:29:36 · answer #5 · answered by trethoma 2 · 0⤊ 3⤋