OK..Easy! Best to work backwards on PROBLEM #1. So, if John made a 70% profit, after originally spending $60, that would mean he NOW has: $102 [60 x 1.70 = 102] so: If he was selling mangoes at 25 cents each, he would have to had sold 408 mangoes to make $102 [102 / 0.25 = 408] NOW: if he had 408 GOOD mangoes to sell, (after having lost 15% to rot), that means 85% (100% - 15% ) of a certain number, x, equals 408....or, expressed algabraically:.. 0.85x = 408..... therefore x = 408/0.85.. or 480....So, this means he ORIGINALLY had 480 mangoes. Finally, if there were 12 boxes and 480 mangoes total, there would be 40 mangoes in each box [480 divided by 12 = 40] SO: The answer to your first question is 40 mangoes in each box, BEFORE losing the rotten ones........so, after he lost 15% there would be only 34 mangoes in each box. PROBLEM #2 Let x = the number of girls. Therefore, x/160 is the original % of girls. If we add 32 girls, the # of girls is now x + 32 and the new total of students is 160 + 32 or, 192,.....and the NEW percentage of girls is represented as: (x + 32) / 192 and the increase of 5% is represented as: (x /160) + .05 All of this can be represented algabraically as: (x +32) / 192 = (x / 160) + .05 Multiply both sides of the equation by 192 to get: x + 32 = (192x/160) + 9.6 Then simplify the equation further by multiplying each value by 160 to get: (160x + 5120 = 192x + 1536) Further simplifying: 32x = 3584 Therefore: x = 112 So, the original # of girls is 112. Therefore 112 girls out of a total of 160 students = 70% (112/160 = 70%) Increase the girls by 32, you have 144 girls and a new total of 160+32 Therefore: 144/192 = 75% for your increase of 5% which proves the solution. Don't forget though!! The question was: HOW MANY BOYS? Of course the answer is 48. (160 minus 112) (Most math teachers are VERY fussy! They want an answer to their question!!)
2007-12-06 20:10:03
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answer #1
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answered by pilota300b4 4
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Second question first:
Let x and y be the number of boys and girls and so a + b = 160. Adding 32 more girls makes the percentage of the girls increase by 5%
[(b + 32) / 192 - b / 160) ] x 100 = 5
b/192 + 32/192 - b/160 = 5/100 = 1/20
b/192 - b/160 = 1/20 - 1/6
160 b - 192 b = 192 x 160 x (3 - 10) / 60 = -7 x 192 x 160 /60
- 32b = - 7 x 192 x 160 / 60
So negative sign can be canceled.
b = 7 x 192 x 160 / (60 x 32)
= 112
So the number of boys is 160 - 112 = 48
Let us verify the results.
Percentage of girls originally = 100x 112/160 = 70
Percentage after 32 more girls join = 100 x 144 / 192 = 75
So, our calculation is correct.
Now let us try the first question:
12 boxes contain 12 x mangoes.
15% of them got spoilt. So, remaining mangoes are 0.85 x 12 x
They were sold at 25 cents each and the resultant amount is 70% more than 60 dollars, the price John paid.
So, 0.85 x 12 x 0.25 x = 1.7 x 60
2.55 x = 102
x = 102/2.55 = 40
So each box had 40 mangoes.
2007-12-06 20:27:07
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answer #2
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answered by Swamy 7
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Here is the solution for the second one:
THe equation you need to solve is this:
(g+32)/(160+32)=(g/160)+.05
The left side represents the percentage of girls when the 32 are added, and the right side tells is equal to it because it is the old percentage plus the 5%.
At this point it is simple algebra, the answer is g=112, or 112 girls, so there are 48 boys in the class.
2007-12-06 20:20:26
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answer #3
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answered by b1gmuff 3
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Solution Provider: Eroz Awari (S.G.M.Shiroiya School, navsari)
Second Question Solution:
Let the number of boys be = x
& the number of girls be = y
Now, From the given data we can form a given below equation:
x + y = 160 -----------------------------Eq.No 1.
y = 160 - x (by applying the algebric rules:)
Now, if 32 more girls join the club, the percentage of girls will increase by 5%. this statement can be mathematically depicted by:
y + 32 = (160 - x) + (160 -x)*5/100
y+32 = (160 -x) + (160 - x)/20
y+32 = [20(160-x) + 160 - x)] /20
20 ( y + 32) = 3200 - 20 x + 160 - x
20y + 640 = 3360 - 21x
21x + 20y = 3360 - 640
21x + 20y = 2720 ----------------------->Eq No 2.
Now, Solve Eq. No 1 & 2
and U will get the answer.
2007-12-06 21:16:14
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answer #4
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answered by eerroozz 2
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let,the no.of girls=x;then,the no. of boys would be=160-x,
the percentage of girls=5x/8
after adding 32 girls--
the total no.of members=160+32=192
total no. of girls=x+32
percentage of girls now=100(x+32)/192
according to the question-
the percentage has been increased by 5%
so,(5x/8)+5=100(32+x)/192
x=112
the no. of boys=160-112=48
i tried my level best,check the answer and let me know that whether its ok or not.the another question is already solved so i didn't try it,if need it also let me know i will solve it for you,byeeeeeeeeeeeeeeeeee,thanks
2007-12-06 20:38:23
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answer #5
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answered by dipanwita B 2
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he number of mangos he will sell is 0.85 * 12 *x
he will sell them 0.25 dollar each
so he will get 0.25 *0.85 *12 x dollars = 2.55 x
70% profit =60*70/100 = 42
so he will get 42+60 =102 $
so
2.55 x =102
x= 102/2.55 = 40
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(g+32)/192 - g/160=.05
160g +32*160 - 192g =0.5*160*192 =1536
-32g + 5120 =1536
32g =5120-1536 = 3584
g=112
b=160-112= 48
so there are 48 boys
2007-12-06 20:07:16
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answer #6
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answered by mbdwy 5
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12x = $60
12x (.85) x .25 = $60 x 1.7 (70 % profit)
2.55x = 10200 ($102.00)
40 mangoes in a box
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5% = 32
can't be - even at 100% girls - a 5% increase would be 8
something is wrong in the problem
2007-12-06 20:10:42
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answer #7
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answered by tom4bucs 7
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whilst that's in parenthesis it contains the two the "-" and the "2". so which you have: (-2)^4 = -2 x -2 x -2 x -2 = sixteen (because of the fact 2 negatives become a helpful whilst it isn't any longer in parenthesis it only contains the variety raised to the flexibility of four so which you have -2^4 = -a million x 2 x 2 x 2 x 2 = -a million x sixteen keep in mind that the -2 is referred to as -a million x 2 because of the fact something circumstances a million is itself
2016-11-13 23:03:19
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answer #8
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answered by ? 4
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