Combinatorial Mathmatic Question?

Question

the questions is
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For which positive integer n will the equestions
(1) x1+x2+x3+...+x19 = n , and
(2) y1+y2+y3+....+x64 = n
have the same number of positive integer solutions?
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since C(n+k-1,k) = #ofsolutions,
i got
(19+n-1)!/19!(n-1)!=(64+n-1)!/64!(n-1)!

but i can't get anywhere then, was my approach wrong?
i hope somebody could help me,,,,at least some tip or hint.

sorry
that's a typo
it's suppose to say
y1+y2+y3+...+y64=n

Answer 1

Well im not sure why you have a series that starts with y and ends with x but i have no clue what the answer is.