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determine all of the values of x such that
sin^5x + cos^5x = 1 and 0 ≤ x ≤ π/2

2007-12-06 16:37:01 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

Well, 0 and 90 degrees obviously works.

Since (Sin(x))^2 + (Cos(x))^2 = 1, then (Sin(x))^5 + (Cos(x))^5 < 1 between 0 and π/2, so that 0 and π/2 would be the only two solutions.

2007-12-06 18:21:35 · answer #1 · answered by Scythian1950 7 · 0 0

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