A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it rests is 0.24 while the coefficient of kinetic friction is 0.12. What maximum distance can the truck travel (starting from rest and moving horizontally with constant acceleration) in 3.0 s without having the box slide?
2007-12-06 16:35:17 · 5 answers · asked by roncho 4 in Science & Mathematics ➔ Physics
yes i do have a book...and yes i am studying...however, i have a long review and the long questions tend to trip me up and when i have a place to start or even the answer...i can figure out what i am doing...besides i have ten more like this...i just need the refresher...
2007-12-06 16:44:04 · update #1
and thank you for the help....i really appreciate it...i have a final in two days and i have a 88.5% in that class...roughly...so i need an A on the final
2007-12-06 16:45:20 · update #2
and jgoulden; I like your approach...i like that you basically did it but still required me to finish it...
2007-12-06 16:49:48 · update #3
The maximum force of static friction is μmg
The maximum acceleration is thus
ma = μmg
a = μg = ( .24 ) ( 9.8 m / s² )
We have the maximum acceleration; now get the distance from kinematics...
d = 1/2 a t²
2007-12-06 16:39:30 · answer #1 · answered by jgoulden 7 · 1⤊ 1⤋
capability on the equilbrium place is all kinetic one million/2 m v² capability on the prolonged place is all ability one million/2 ok A² Compute them the two and take the adaptation; the loss is the paintings executed by making use of friction. Set that paintings equivalent to rigidity x distance to get the traditional rigidity of friction. That rigidity is ?mg the place ? is the coefficient of kinetic friction.
2016-10-10 11:00:31 · answer #2 · answered by ? 4 · 0⤊ 0⤋
C'mon you should study these kind of things! You shouldn't make other people do your work.
2007-12-06 16:39:08 · answer #3 · answered by Anonymous · 0⤊ 2⤋
How about we study and try really hard and do OUR OWN work?
2007-12-06 16:37:23 · answer #4 · answered by Anonymous · 1⤊ 1⤋
umm...don't you have a physics book with a formula in it do solve this problem???
2007-12-06 16:37:37 · answer #5 · answered by Artist Wanna Be 4 · 0⤊ 1⤋