Molarity help? how to make a 3% solution?

Question

i am trying to make a 3%
-salt / NaCl
-sugar/ C6H12O6
-asprin/acetylsalicylic acid / C9H8O4
with 500 mL of each water.

How would i make it? would i use 3% of 500 ml (15 grams) of each solute and dissolve it into water?
if not, how much solute would i need and how would i do it?
i'm doing this for a science fair w/ a partner, and the teacher didn't really help us much...so help please!

Answer 1

All the three solutes are SOLIDS--.Keep all the solids in a desicator over the porcelain slieve in the upper chamber,the lower chamber containing a dehydrant for about 30 minutes.Then weigh exactly 15 grammes of each solid --put each solid in a seperate measuring Cylinder (500 ml capacity) and dissolve in a small amount of distilled water and make up the volume in each cylinder to 500ml.Acetyl salicylic acid may require about 2 drops of dilute NaOH to convert the acid to sodium salt which will dissolve easily.They will be 3% solution of each solute.

Answer 2

If it's 3%, you have 3 mL of the solute per 100 mL of the solvent (water). [3/100 = .03 = 3%] If you have 500 mL of water, you need 15 mL of solute.