A liquid ( = 1.65 g/cm3) flows through two horizontal sections of tubing joined end to end. In the first section the cross-sectional area is 10.0 cm2, the flow speed is 265 cm/s, and the pressure is 1.20 105 Pa. In the second section the cross-sectional area is 2.50 cm2. Calculate the smaller section's pressure.
2007-12-06 16:05:13 · 1 answers · asked by shalini p 1 in Science & Mathematics ➔ Physics
Bernoulli's Equation
P + ρ g h + 1/2 ρ v² = constant
Your heights are the same, so the middle term can be ignored.
P1 + 1/2 ρ v1² = P2 + 1/2 ρ v2²
You also know that in the flow of an incompressible fluid,
the product of velocity and area is a constant
v1 A1 = v2 A2
You know one velocity and both areas, so use that last equation to get the second velocity. Then plug everything into Bernoulli's Equation to find the unknown pressure.
2007-12-06 16:34:40 · answer #1 · answered by jgoulden 7 · 0⤊ 1⤋