Factor the polynomial completely
4x^5 - 20x^4 - 24x^3
2007-12-06 15:40:56 · 8 answers · asked by Anonymous in Education & Reference ➔ Homework Help
take out a 4x^3
4x^3(x^2-5x-6), the stuff in the parenthesis can be factored too
4x^3(x+1)(x-6)
2007-12-06 15:44:37 · answer #1 · answered by dohboy000 4 · 0⤊ 0⤋
4x^5 - 20x^4 - 24x^3
answer
Completely by terms (4x^3) (x+1) (x-6)
Completely by multiples 4(x) (x) (x) (x+1) (x-6)
2007-12-06 16:00:23 · answer #2 · answered by cameron m 2 · 0⤊ 0⤋
Start by dividing the ploynomial by 4x^3
4x^3(x^2-5x-6)
Then factor the (x^2-5x-6)
as (x-6)(x+1)
so you get
(4x^3)*(x-6)*(x+1)
2007-12-06 15:45:06 · answer #3 · answered by gator_ce 5 · 0⤊ 0⤋
4x^5 - 20x^4 - 24x^3
4x^3(x^2-5x-6)
4x^3(x-6)(x+1)
2007-12-06 15:47:47 · answer #4 · answered by pill_pushr 3 · 0⤊ 0⤋
Factoring polynomials completely: x^3y + 2x^2y^2 + xy^3 Factor out the Greatest Common Factor (GCF) = xy xy(x^2 + 2xy +y^2) Factor a trinomial xy(y + x) (y +x) Final result: xy(y + x) (y + x)
2016-05-21 23:07:27 · answer #5 · answered by ? 3 · 0⤊ 0⤋
well first you can factor out a 4x^3.
4x^3(x^2-5x-6) now you can further factor the quadratic equation.
(4x^3)(x-6)(x+1)
2007-12-06 15:45:27 · answer #6 · answered by Anonymous · 0⤊ 0⤋
4x^3 (x^2 - 5x - 6)
4x^3 (x - 6) (x + 1)
2007-12-06 15:46:27 · answer #7 · answered by Steve B 6 · 0⤊ 0⤋
4x^3(x^2-5x-6)
4x^3(x-6)(x+1)
2007-12-06 15:45:22 · answer #8 · answered by Anonymous · 0⤊ 0⤋