1.6x2 - 4x - 3 = 0
2.x2 - 3x - 40 = 0
3.(x + 4)2 = 16
2007-12-06 15:00:37 · 4 answers · asked by ry ry 3 in Science & Mathematics ➔ Mathematics
factor, the set each factor = to 0
1} 6x2 - 4x - 3 = 0
I think this one needs quad formula
2} x^2 - 3x - 40 = 0
(x-8)(x+5)=0
x-8=- x+5=0
x=8 x=-5
3.(x + 4)2 = 16
2x+8=16
2x=8
x=4
BUT if you meant (x + 4)^2 = 16
x+4=+-4
x=0 or x=-8
2007-12-06 15:07:48 · answer #1 · answered by RickSus R 5 · 1⤊ 0⤋
1. use the quadratic formula because it's not factorable
2. (x-8)(x+5), so x=8 and x= -5
3. x+4 = 4, so x=0
2007-12-06 15:06:47 · answer #2 · answered by IE 3 · 0⤊ 0⤋
It doesn't look like these factor so use the general solution for the quadratic equation:
If ax^2 + bx + c = 0, then
x = ( -b +/- sqrt ( b^2 - 4 a c ) ) / 2a
2007-12-06 15:04:34 · answer #3 · answered by jgoulden 7 · 0⤊ 0⤋
2.(x-8)(x+4) therefore, x=8 and x=-4
3.x=4
1. not sure if it can be reduced?
2007-12-06 15:07:56 · answer #4 · answered by scott D 2 · 0⤊ 0⤋