how is this math equation wrong?

Question

(this ^ means to the power or expoinent whatever)

-6a^-2
-------------(over)
p^5

how is that not equal to

1
----------------(over)
6a^2q^5

Answer 1

answer
-6
----------(over)
a^2 q^5

Answer 2

(-6a^-2/p^5) x (6q^5p^-5/6q^5p^-5) =

-36q^5p^-5 / 6a^2q^5.
[Multiplying the numerator and denominator of a fraction by the same number or equation can't change the ratio.]

For the equations above to be equal, -36q^5p^-5 must equal 1. Or - 36 q^5 must equal p^5.
This is possible if q is + and p is - or vice versa..
It is not possible if both are + or both are - . Since it isn't always possible, it is not a true equality.
[A positive number to an odd power is always + and a - number to an odd power is always -. Then one side of an equality can't be + while the other side is -.]

Answer 3

One of the rules of exponents is that

a^n = 1 / a^-n

So -6a^-2 / p^5 is equal to -6 / a^2 p^5 (not quite what you posted)

Answer 4

the answer should be
1p^5
______
6a^2

i pretty sure thats right

the power does not stay negative because the whole point of this is to get the exponent not negative.

remember this rule " when you cross the line, change the sign" thats what my teacher told us

Answer 5

First of all, you dropped the negative (there is a negative in the numerator of the first one and not in the second one)
And second of all 6 (in the numerator of the first one) is not raised to the power of -2, only a is. So you can't move 6 to the denominator, only a. The correct answer would be:

-6
-------------
(a^2*p^5)

Hope this helps! :)

Answer 6

-6 does not equal 1/6;
but a^-2 = 1 / a^2

so it should be -6 / a^2q^5

Answer 7

Its wrong because the variables are different and moreover the power of a in both cases is not the same.

Answer 8

the power (-2) stays negative

Answer 9

your first equation is negative, and your second is not. Also, there is "q^%" in the second one, but i'm assuming you were referring to p^5. other than that, its fine