how do you factor x^2+x-6???? i need the answere andthe syeps tp learn from it!!!! please!!!!?

Question

i know its somthing like (x )(x ) help!!!!!!!!!!!!!

Answer 1

(x+3)(x-2)
x=-3,2

ok x^2 means 2x's, the +x=1x which means that the sum of the 2 numbers is 1 and -6 means the 2 numbers product is -6

or you can use the quatractic formula-if you didn't learn it then you will after that chapter.

Answer 2

The standard form of an equation is ax^2 + bx + c

Hence in the given equation
a = 1
b = 1
c = -6

Now to solve this equation, you need to find any two number which when added give b, and when multiplied give a * c

i.e. if the 2 numbers are x and y,
x + y = 1
x * y = a * c

Best way to go about this is to find the factors of a * c In this case 6
6 = 6 * 1 or
6 = 3 * 2

If you notice in the standard equation there are no negative signs. However in the given equation c is a negative number and hence a * c will be a negative number. Hence on of the factors of 6 HAS to be a negative number.

As you can see there are only two option that give you 6 here. Now you need to check in which of the cases, the factors when added (don't forget that one of them will be a negative number and hence in reality we'll be subtracting them) give you 6.

Difference between 6 and 1 (the first factors we found) is 5
Similarly the difference between 3 and 2 is 1 <== we have a winner.

So now which of these factors will be the negative number? Look at b. It's a positive number. Hence the bigger of the two factors (3 and 2) cannot be the negative number. So the factors are 3 and -2

You now have to put this into your equation. But how do you know which factor comes first? For that you need to compare a and c. c is the bigger number in this case and hence the smaller factor should be placed closer to c.

Hence this equation x^2 + x - 6 now becomes
x^2 + 3x - 2x - 6

You now take the first 2 components of the equation (i.e. x^2 + 3x). What is common? Just x. We hence take the common factor out and shove the rest in a bracket.
x(x + 3)

We now do the same for the last 2 components (i.e. -2x - 6). -2 is the common factor. Hence
-2 (x + 3)

NOTE that whatever remains in the brackets will always be the same. If it's not, you've made some mistake.

So your in entirety, you equation is now
x (x + 3) -2 (x + 3)

You now move all the unbracketed terms to one side and since x + 3 is common, it will be put to the other side. Hence what you get is
(x + 3) (x - 2)

If you take each of these separately, it means that either
x + 3 = 0 or x - 2 = 0

Keeping the x on one side of the equations and moving the other components to the other side you get
x = -3 or x = 2

This my friend, is your answer :) However when writing it down you just have to write it as below.

=============

x^2 + x - 6
= x^2 + 3x - 2x - 6
= x (x + 3) - 2 (x + 3)
= (x + 3) (x - 2)
Hence x + 3 = 0 or x - 2 = 0
Hence x = -3 or 2

Answer 3

x^2 + x - 6 =
(x + 3)(x - 2)

Answer 4

(x+3)(x-2)

seeing that 3 * (-2) will give you negative 6 but once you subtract 3x - 2x you still end up with a positive x

Answer 5

x^2 + x -- 6
= x^2 + 3x -- 2x -- 6
= x(x + 3) -- 2(x + 3)
= (x + 3)(x -- 2)

Answer 6

x^2+x-6

(x-2)(x+3)

x*x=x^2
-2*x=-2x
3*x=3x
2*-3=-6

x^2-2x+3x-6
x^2+x-6