Find the domain: f(x) = x^3 -1/ x^2 -4?

Answer 1

is it (x³-1)/(x² - 4)?
since x² - 4 = (x+2)(x-2), either x = 2 or x = -2 will have us dividing by 0, which is not allowed, so the domain is all real numbers except for ±2.

Answer 2

(x^3 -1)/(x^2 -4) There is no f(x) value when the denominator is 0.
When is the denominator zero? Solve:
x^2-4=0 x^2=4
x= (+/-) 2
x cannot be positive 2 or negative 2... in fancy math notation:
D=x:x∈{(-∞,-2)U(-2,2)U(2,∞)}

Answer 3

I think the only way to answer this question, is if they would give you a value for the X in f(x), then you would just pop that value into the x's along the way, then simplify, otherwise I don't know what to do! Sorry!

Answer 4

{x/x(not equal)+/-2}

Answer 5

can you use different symbols im not sure what ^ means